Question

The work done by a system is 8 joule, when 40 joule heat is supplied to it , what is the increase in internal energy of the system ?

a.25 j

b.30 j

c.32 j

d.28 j

Answer 1

Answer:

dQ=40 J dw=−8 J

dQ=du+dw

du=dQ−dw=40−(−8)=48 J

Therefore there is a increase in internal energy of a system by 8 J

∴ du=48 J

Explanation:

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