Question

The work done by battery to transfer a charge of 8×10^-18 C on a condenser of capacity 100 micro farad is :- (1) 16×10^-32J (2) 3.1×10^-26J (3) 64×10^-32J (4) 32×10^-42J

Answer 1

Given:

Charge transferred to Capacitor is 8 × 10^(-18) C, capacitance of Capacitor is 100 micro-F.

To find:

Work done to charge the Capacitor

Calculation:

General formula for work done in charging a capacitor is :

$\boxed{ \sf{work = \dfrac{ {Q}^{2} }{2C} }}$

Putting all the available values :

$\sf{ = > work = \dfrac{ {(8 \times {10}^{ - 18}) }^{2} }{2 \times 100 \times {10}^{ - 6} } }$

$\sf{ = > work = \dfrac{ {(8 \times {10}^{ - 18}) }^{2} }{2 \times {10}^{ - 4} } }$

$\sf{ = > work = \dfrac{ 64 \times {10}^{ - 36}}{2 \times {10}^{ - 4} } }$

$\sf{ = > work = \dfrac{ 32 \times {10}^{ - 36}}{ {10}^{ - 4} } }$

$\sf{ = > work = 32 \times {10}^{ - 32} \: Joule}$

So, final answer is:

$\boxed{ \rm{ \large{work = 32 \times {10}^{ - 32} \: J}}}$