the work done by external force in stretching a spring having spring constant k is equal to hundred newton per metre by 10 cm from its unstretched position is
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Work done =-1/2kx²
where k is equal to 100 N/m and x=10/100=0.1 m
W=-1/2×100×(0.1) ²
W=-50×1/100
W=-1/2=-0.5 J
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