Question

The work done by friction on system in displacement 10 m is :
5 kg
100N
u=0.5
(1) Zero
(2) -120
(3) -250J
(4) -1000 J​

Answer 1

Answer:

zero

Explanation:

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Answer 2

Given:

The system in displacement $10m$, $5Kg$, $100N$,$u=0.5$.

To find:

The work done on system in displacement.

Explanation:

$F_{n}=F-umg$$*s$

$W_{net}=(100-0.5*5*5)*10$

$=(100-125)*10$

$=-25*10$

$=-250J$

Answer:

Therefore, The work done on system in displacement in $-250J$.