Question

The work done by friction on system in displacement 10 m is :
5 kg 100N

Zero
-120J
-250J
-1000 J​

Answer 1

Answer: 3) -250 J

Explanation:

Work Done = force * displacement

Now lets find force applied on object by friction

F of friction = uN

=0.5*5*10---(g=10m/s^2)

= - 25 N

Now work done = F*s =  -25*10= -250 J

Answer 2

Answer:

The work done by friction on the system in displacement 10 m is :$-250J$

Explanation:

• The work done can be obtained by the expression,

        $\text\ {Work done = Force \times displacement}$

        Let W be the work done, F be the force and d be the displacement

        then,

       $W = F\times d$              ...(1)

       In this case, the frictional force is given by,

       $F = \mu N$        

       Where $\mu$is the coefficient of friction and N is the normal force

      $N = mg$  

      m is the mass of the block and g is the acceleration due to gravity.

       That is, $F = \mu mg$      ...(2)

• In the question, it is given that,

        $m = 5kg$         $g = 10 m/s^2$

        $\mu = 0.5$            $d = 10m$

        Using equation (2),

        $F = 0.5\times 5\times 10= 25N$

        Then substitute these values into equation (1),

        We get,

         $W = 25\times 10 = -250J$

        Option(3) is the correct answer.