Question

The work done by the man on 20 kg load is equal to (g = 10 ms-2)
a) 2400 J
b) 800J
c) 1000 J​

Answer 1

Correct question:

• The work done by a person in lifting a load of 20kg from the ground and floating it 12 m high on a table.

Answer:

Explanation:

Given :

• Mass (m) = 20 kg
• Height (h) = 12 m
• Acceleration due to gravity (g) = 10 m/s²

To Find :

• Work done by the man, W

Formula to be used :

• W = mgh

Solution :

Work done,

W = mgh

⇒ W = 20 × 10 × 12

⇒ W = 2400 J

Hence, the work done by the man is 2400 J.

Answer 2

Correct Question:-

$\bigstar$Find the work done by a person in lifting a load of 20 kg from the ground and floating it 12 m high on a table?

Given:-

$\bigstar$A person is lifting a load of 20 kg from the ground.

$\bigstar$The load is floating in the height of 12 m high on a table.

Find:-

$\bigstar$The work done by the person?

Solution:-

$\bigstar$We are given that, A person is lifting a load of 20 kg from the ground and the load is floating in 12 m high on table. To find the work done by person. We are using formula:

$\star { \boxed{ \boxed{{ \sf{ \red{Work done = Mass × Gravity × Height} }}}}} \star$

$\dashrightarrow \sf Work \: done = 20 \times 10 \times 12$

$\dashrightarrow \sf Work \: done = 200 \times 12$

$\dashrightarrow \sf Work \: done = 2400 \: J$

$\bigstar$Hence, The work done by the person is 2400 J.