The work done by the push of air on an object of mass 10 kg falling from rest through a vertical distance of 10 m is 500 J. Find the velocity of the object at the end of 10 m fall: (g = 10 m/s2)
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Answered by
1
Answer:
Explanation:
An object mass 10 kg falls from rest through a vertical distance of 10 m and acquires a velocity of 10 m/s. The work done by the push of air on the object is (g=10m/s2).
Answered by
0
Answer:
Given that,
Mass of object, m=10Kg
Velocity, v=10m/s
Vertical distance, h=10m
From work energy theorem:
Work done by weight + work done by air = KE
W
air
=KE−W
weight
=
2
1
mv
2
−mgh
=
2
1
×10×10×10−10×10×10
=−500J
The work done by the push of air on the object is -500 J.
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