Question

The work done by the push of air on an object of mass 10 kg falling from rest through a vertical distance of 10 m is 500 J. Find the velocity of the object at the end of 10 m fall: (g = 10 m/s2)​

Answer 1

Answer:

Explanation:

An object mass 10 kg falls from rest through a vertical distance of 10 m and acquires a velocity of 10 m/s. The work done by the push of air on the object is (g=10m/s2).

Answer 2

Answer:

Given that,

Mass of object, m=10Kg

Velocity, v=10m/s

Vertical distance, h=10m

From work energy theorem:

Work done by weight + work done by air = KE

W

air

=KE−W

weight

=

2

1

mv

2

−mgh

=

2

1

×10×10×10−10×10×10

=−500J

The work done by the push of air on the object is -500 J.