Question

The work done by (x-3) men in (2x+1) days and the work done by (2x-1) men in (x+4) days are in the ratio of 3:10. Find the value of x.

plz answer ASAP​

Answer 1

${\huge {\mathfrak {\orange {Answer :-}}}}$

$<b>$ ➡️ First scenerio,

Work done by (x - 3) men in (2x + 1) days is

= (x - 3)(2x + 1)

= 2x^2 + x - 6x - 3

= 2x^2 - 5x - 3 ⬅️

➡️ Second scenerio,

Work done by (2x - 1) men in (x + 4) days is

= (2x - 1)(x + 4)

= 2x^2 + 8x - x - 4

= 2x^2 + 7x - 4 ⬅️

Given that, these works are in the ratio 3 : 10

By condition,

(2x^2 - 5x - 3)/(2x^2 + 7x - 4) = 3/10

Or, 10(2x^2 - 5x - 3) = 3(2x^2 + 7x - 4)

Or, 20x^2 - 50x - 30 = 6x^2 + 21x - 12

Or, 14x^2 - 71x - 18 = 0

Or, 14x^2 - 74x +3x - 18 = 0

Or, 14x(x - 6) + 3(x - 6) = 0

Or, (x - 6)(14x + 3) = 0

Or, x = 6, - 3/14

The number of days can't be negative, so, the value of x can't be negative.

➡️ Hence, value of x = 6. $</b>$

$<i>$ That's it..

${\red {-:Arnab \: here :-}}$
$<marquee >$
${\huge {\blue {Thanks}}}$

Answer 2

Step-by-step explanation:

First scenerio,

Work done by (x - 3) men in (2x + 1) days is

= (x - 3)(2x + 1)

= 2x^2 + x - 6x - 3

= 2x^2 - 5x - 3 .