Chemistry, asked by vishaljammulamudi, 9 months ago

The work done during the expansion of a gas from
4 dm to 6 dm against a constant external pressure
of 3 atm is (1 L atm = 101.32 J)
(a) - 6J
(b) - 608
(c) + 304J
(d) - 304what will be the work done when 1 mole of gas expands isothermally from 15 litres to 50 litres against a constant pressure of 1 atmosphere at 25 degree Celsius ​

Answers

Answered by kumarjha1992
0

Answer:

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