The work done during the expansion of a gas from a volume of4dm3 to 6 dm^{ 3}$ against a constant external pressure of 3 atm is :-
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Answer : The work done during the expansion of a gas is .
Solution : Given,
Initial volume of gas =
Final volume of gas =
Pressure of gas = 3 atm
Formula used :
where,
W = work done of a gas
P = pressure of a gas
= final volume of a gas
= initial volume of a gas
Now put all the given values in above formula, we get the work done of a gas.
Therefore, the work done during the expansion of a gas is
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