Chemistry, asked by wadhwanineha30, 1 year ago

the work done during the expansion of a gas from a volume of 4 dm3 and 6dm3 against a constant external pressure of 3 atm

Answers

Answered by jayprakash110202

2

Answer;6 multiply by 10 power 2

Explanation:

p[v2-v1]=work done at constant pressur

1atm=10power5pa

1dm3=10power-3m3

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