The work done during the following process
Attachments:
Answers
Answered by
0
Answer:
π\4(p2-p1). hope you get the answer
Answered by
0
Answer:
The Answer is below...
Explanation:
(i) Work done in the process A→B (the process is expansion, hence work done by the gas)
=−P×dV=−12×10
5
×5×10
−3
=−6000J
Work done in the process B→C is zero as volume remains constant.
Work done in the process C→D (the process is contraction hence work done on the gas)
=P×dV=2×10
5
×6×10
−3
=1000J
(ii) Work done in the process D→A is zero as volume remains constant.
Net work done in the whole cycle =−6000+1000=−5000J
i.e., net work is done by the gas.
Hope You Got Benefitted Out Of This ....
Please Mark me as Brainlist and also me as mamy as Thanks for this Effort
Similar questions