Question

The work done for rotating a magnet with magnetic dipole moment M, through 90° from its magnetic is N time the work done to rotate it through 60°. Find the value of N​

Answer 1

answer

N =2

explanation

W=MB(cos0−cos90)=MB

W1=MB(cos0−cos60)=0.5MB

n=2

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Answer 2

$\bigstar$ Given

The work done for rotating a magnet with magnetic dipole moment M, through 90° from its magnetic is N time the work done to rotate it through 60°

$\bigstar$ To Find

The value of N​

Solution

Given that,

Magnetic dipole moment = M

Initial angle when magnet is rotated = 90°

$\sf \longrightarrow W_{1}=MB(\cos 0^{0}-\cos 90^{0})$

$\sf \longrightarrow W_{1}=MB$

Final angle when magnet is rotated = 60°

$\sf \longrightarrow W_{2}=MB(\cos 0^{0}-\cos 60^{0})$

$\sf \longrightarrow W_{2}=\dfrac{MB}{2}$

Given that,

The work done for rotating a magnet with magnetic dipole moment M, through 90° from its magnetic is N time the work done to rotate it through 60°

Therefore,

$\sf \longrightarrow W_{1}=N \times W_{2}$

Substituting the values,

We get,

$\sf \longrightarrow MB=N \times \dfrac{MB}{2}$

$\sf \longrightarrow N= 2 \times \dfrac{MB}{MB}$

Cancelling similar terms,

We get,

$\sf \longrightarrow N= 2$