Question

the work done in accelerating an object along a horizontal surface is equal to the objects change in?

Answer 1

Answer:

. Block A is pulled with constant velocity up an incline as shown in the diagram below. ... The work done in accelerating an object along a frictionless horizontal surface is equal to the object's change in (1) momentum (2) velocity (3) potential energy (4) kinetic energy.

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Answer 2

Answer:

The work done in accelerating an object along a horizontal surface is equal to the objects change in kinetic energy.

Work done is the product of the force applied to a body and its displacement.

Therefore, $Work\:Done=F\:.\:d$

It is a scalar quantity and hence, direction is not required.

Let v = final velocity

u = initial velocity

$Change \:in\: Kinetic\: Energy = \frac{1}{2} m (v^{2} -u^{2} )$

We already know $v^{2} -u^{2} =2ad$;

where, a = acceleration and d = distance traversed.

Substituting this value,

$Change \:in\: Kinetic\: Energy = m. a. d$

Now, $m\: . \:a = F$

$Change \:in\: Kinetic\: Energy = F\: .\: d =Work \:Done$

Thus, it is proved that work done in accelerating an object is equal to change in kinetic energy of an object.