The work done in an open vessel at 300 k when 56 g iron reacts with dilute hcl is
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We know that Molar mass of Fe = 56 and R = 2 cal^-1 K mol^-1
W = P(nRT/P) n = 56/56 = 1
= 1 * 2 * 300
= 600 cal.
Hope this helps!
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