Question

The work done in breaking a water drop of radius 1mm to 1000 droplets.surface tension of water is 72*10^3 n/ m

Answer 1

Explanation:

R=10^-3

s=72×10^-3

n=1000

w=surface tension ×increase in surface area

=4/3×p×R^3=4/3×p×r^3×1000

1000r^3=R^3

r=R/10

increase in surface area=1000×4×p×r^2-4×p×R^2

=4×3.14(1000(R^2/10)-R^2)

=12.56×R^2×9

=113.04×(10^-3)^2

=11.04×10^-6

w=72×10^-3×113.04×10^-6=8138.88×10^-9

=8.14×10^-6j