Question

The work done in bringing 5 C of charge from inifinity to a point A near a charged body is 20 J. Find the potential at point, A.​

Answer 1

Explanation:

Q= 5c, W= 20 J. so, V= W/Q

V= 20/5

V= 4volt

therefore the potential difference at point A is 4 volt

Answer 2

Answer:

$\huge\underline\bold {Answer:}$

Electric potential, V = 20 V

Work done, W = 600 J.

We know, W = V q

Therefore, q = W/V = 600/20 = 30 C.

So, magnitude of a charge that can be moved from infinity to a point in an electric field where the potential is 20 V, by spending 600 J of work is 30 C.