Question

The work done in bringing two electrons from a distance of 2m to 1m in air,

where e in electronic charge and k is electrostatic force constant.​

Answer 1

Answer:

see the photo...

answer and solutions both are given

Answer 2

Given: Two electrons are brought from a distance of 2 m to 1 m in air

To find: The work done in bringing the charges closer

Explanation: d= 2m - 1 m = 1 m

Force exerted by an electron on the other:

F = k q^2/d^2 where q is the charge of electron, k is a constant whose value is 9* 10^9 and d is the distance between the charges

Charge of electron= 1.6* 10^-19 C

F = 9* 10^9 * (1.6*10^-19)^2 / 1^2

= 9* 10^9* 2.56* 10^-38 /1

= 23.04* 10^ -29 N

Therefore, work done= Force * distance

= 23.04* 10^-29* 1

= 2.3* 10^-28 J

Therefore, the work done in bringing 2 electrons from 2 m to 1 m is 2.3* 10^-28 J.