The work done in dragging a block of mass 5 kg on an inclined plane of height 2 m is 150 joule the work done against the frictional force will be
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total work done(w) = work done against + friction (w1) + work done against gravity (w2)
total work done(w) = 150j
mass = 5kg
weight=5*9.8= 49N
height= 2m
w= w1+w2
w= w1+ (w*h)
150=w1(49*h)
w1=150-98
w1= 52
hence work done against friction is 52j
jas241001:
a toy gun consists of a sprin and a rubber dart of mass 10 g when compressed by 4cm and released it projects the dart to a height of 2 m if compressed by 6 cm the height achirved will be
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