Question

"The work done in heating one mole of an ideal
gas at constant pressure from 15°C to 25°C is​

Answer 1

Answer:

25R

Explanation:

for process involving constant pressure:-

n.cp.∆t = nR∆t + n.cv.∆t

CV for ideal gas=3/2R

putting value on eqn:-

n.cp.∆t = n∆t(R+3/2R)

=n.∆t.5/2R. (∆t=25-15=10°c)(n=1)

=5/2R×1×10

=25R