Question

The work done in heating one mole of an ideal gas at constant pressure from 15 *Celsius to 25*celsius

Answer 1

ANSWER:-
W=83.14J and the solution is provided in the attachment.

Answer 2

Hello Dear ,

From ideal gas laws,

at constant pressure ,W = nRΔT

Here n = 1 mole , R = 8.314 joules / mole  , Δt = 25° - 15° = 10°C

  ∴ W = 1 × 8.314 × 10

          = 83.14 joules

Hence ,

The work done is 83.14 joules.

Hope it helps !!!