Question

The work done in increasing the temperature of 1 mole ideal gas from 0 °C to 100 °C at constant pressure is ...........
(A) 8.3 × 10⁻³ J
(B) 8.3 × 10⁻² J
(C) 8.3 × 10² J
(D) 8.3 × 10³ J

Answer 1

35. One mole of ideal gas expands isother-

mally to double its volume at 27°C. Then,

the work done by the gas is nearly

Answer 2

Answer:

(C) 8.3 × 10² J

Explanation:

Given,

number of mole, n = 1

initial temperature = 0 °C

final temperature = 100 °C

change in temperature = final temperature - initial temperature

                               ΔT = 100 - 0

                                    = 0

work done can be give by

    W = n.R.ΔT

Putting, R = 8.314 J/ K mol , ΔT =100 and n = 1

=>  W = 1 x 8.314 x 100 j

=>  W = 8.314 J/k mol x 100 k

=>   W = 8.3 × 10² J

Hence, the work done is W = 8.3 × 10² J