Question

The work done in joules in increasing the extension of a spring of stiffness 10n/cm from 4cm to 6cm

Answer 1

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Answer 2

Answer:

Work done, W = 0.0001 J

Explanation:

It is given that,

Stiffness of the spring, k = 10 N/cm = 0.1 N/m

Initial position, x₁ = 4 cm = 0.04 m

Final position, x₂ = 6 cm = 0.06 m

We need to find the work done in increasing the extension of a spring from initial to final position. We know that the work done is equal to the change in potential energy of the spring.

$W=U_f-U_i$

$W=\dfrac{1}{2}k(x_2^2-x_1^2)$

$W=\dfrac{1}{2}\times 0.1\ N/m\times (0.06^2-0.04^2)$

W = 0.0001 J

So, the work done by the spring is 0.0001 Joules. Hence, this is the required solution.