the work done in lifiting a 10 kg load of bricks to the top of a building 20 m high is(g=9.8ms)
Answers
Answered by
10
Explanation:
it is
20×10=200
200×9.8=1960
Answered by
17
Answer:
1960J
Explanation:
m = 10 kg
h = 20 m
Work done against gravitational force,
W = mgh
= 10 x 9.8 x 20
= 1960 J
Similar questions