Physics, asked by sumathireddy525, 8 months ago

the work done in lifiting a 10 kg load of bricks to the top of a building 20 m high is(g=9.8ms)

Answers

Answered by roopchand2000

10

Explanation:

it is

20×10=200

200×9.8=1960

Answered by kirankumarr121005

17

Answer:

1960J

Explanation:

m = 10 kg

h = 20 m

Work done against gravitational force,

W = mgh

= 10 x 9.8 x 20

= 1960 J

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