The work done in lifting a load of 300 N weight to height of 10 m with an acceleration 0.5 ms is (g=10 m/s²)
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3150j
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The work done in lifting a load of 300 N weight to height of 10 m with an acceleration 0.5 ms is (g=10 m/s²)
Answered by
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Answer:
weight = 300N
mass = 300/10 = 30 kg
accleration = 0.5 ms
height = 10m
work done = energy = 30×0.5×10 = 150 joules
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