Question

The work done in moving a body between potential difference of 10 volt is

15 joule calculate the magnitude of charge ?​

Answer 1

Answer:

1.5 Coulombs

Explanation:

Given,

Potential Difference = 10 Volts

Work Done = 15 Joule

We know that,

Work done = Potential Difference × Charge

15 = 10 × Charge

Charge = 15/10

Charge = 1.5 Coulomb.

Thus the magnitude of the charge is 10 Couloubs.

Note :- V = W/q

If we choose q = 1

V = W

Thus,

Potential Difference between two terminal is the work done by moving a unit charge from one point to terminal to another point.

Answer 2

Answer:

$\large{\underline{\boxed{\mathfrak\blue{Magnitude \: of \: charge = 1.5 \: C }}}}$

$\rule{100}{2}$

Question:-

The work done in moving a body between potential difference of 10 volt is 15 joule.Calculate the magnitude of charge.

Given:-

• Potential difference (v) = 10 volt

• Work done (w) = 15 joule.

To find:-

• Magnitude of charge = ?

We know,

$\star\: {\boxed{\sf\green{Potential \: difference(v) = \dfrac{Work \: done(w)}{Magnitude \: of \: charge(q)} }}}$

•°•  W = V × q

➳ q = W/V

➳ q = 15/10

•°• q = 1.5 C [Required Answer]

$\therefore$ Magnitude of charge = 1.5C

$\rule{200}{2}$

Some more informations:-

Another examples using that formula:-

What potential difference is required to do 100 J of work to carry a charge of 10 C between two points?

Solution:-

As given,

• Work done (W) = 100J
• Magnitude of charge = 10C

To find:-

• Potential difference (V) = ?

Now,using the formula:-

$\star\: {\boxed{\sf\green{Potential \: difference(v) = \dfrac{Work \: done(w)}{Magnitude \: of \: charge(q)} }}}$

➳ Potential difference(v) = 100/10 V

➳ Potential difference = 10 V

$\rule{100}2$

Another example:-

Calculate the potential difference between two points, if 1500 J of work is done to carry a charge of 50C from one point to other?

Solution:

Given:-

• Work done (W) = 1500J

• Charge (Q) = 50C

To find:-

• Potential difference (v) = ?

We know that,

➜ W = V × q

➜ V =1500J / 50 C

➜ V = 30 V

$\rule{200}{1}$