Question

The work done in moving a body of mass 5kg from the bottom of a smooth inclined plane to the top is 50J. If the angle of inclination
of the inclined plane is 30°, its length is (g = 10 ms-2) (in metre)​​

Answer 1

Answer:

The displacement against the gravitational force is Ssinθ

or

10sin30

o

=5m

Thus we get the work done as gravitational force x displacement (in vertical direction)

5g×5=250 J