Question

The work done in moving a charge of 9 Coulomb between two points which are 9cm apart in an electric field is found to be 18J. What is the Electric Potential Difference between the 2 points?

Answer 1

Given :

The work done in moving a charge of 9 coulomb between two points is 18J.

To Find :

Electric potential difference between two points.

Solution :

❒ Work done in moving a charge of Q coulomb from one point (at 0 volt potential) to another point (at V volt potential) in an electric field is given by

• W = Q × ∆V

» W denotes work done

» Q denotes charge

» ∆V denotes potential difference

By substituting the given values;

➙ 18 = 9 × ∆V

➙ ∆V = 18/9

➙ ∆V = 2 volts

Knowledge BoosteR :

• Electric potential is a scalar quantity while potential gradient is a vector quantity.
• The electric potential near an isolated positive charge is positive because work has to be done by an external agent to push a positive charge in, from infinity.
• The electric potential near an isolated negative charge is negative because the positive test charge is attracted by the negative charge.
• The electric potential due to a charge q at its own location is not defined-it is infinite$.$

Answer 2

Given :

The work done in moving a charge of 9 coulomb between two points is 18J.

To Find :

Electric potential difference between two points.

Solution :

❒ Work done in moving a charge of Q coulomb from one point (at 0 volt potential) to another point (at V volt potential) in an electric field is given by

W = Q × ∆V

» W denotes work done

» Q denotes charge

» ∆V denotes potential difference

By substituting the given values;

➙ 18 = 9 × ∆V

➙ ∆V = 18/9

➙ ∆V = 2 volts

Knowledge BoosteR :

Electric potential is a scalar quantity while potential gradient is a vector quantity.

The electric potential near an isolated positive charge is positive because work has to be done by an external agent to push a positive charge in, from infinity.

The electric potential near an isolated negative charge is negative because the positive test charge is attracted by the negative charge.

The electric potential due to a charge q at its own location is not defined-it is infinite$.$