Question

The work done in moving a particle from a point
(1, 1) to (2, 3) in a plane in force field with potential
U = k(x + y) is
(1) 3k
(2) -3k
(3) K
(4) Zero
​

Answer 1

Answer:

Ans......

F=dw/dx

=-3k j

Answer 2

Given:

Point one = ( 1, 1 )

Point two = ( 2, 3 )

To Find:

Work done in Potential U =  = k(x + y)

Solution:

Using the formula for the field -

F = u/xi - u/xj

U = K ( x + y )

Therefore,  

Substituting the values -

F = - Ki - Kj

r = ( 2i + 3j ) - ( i + j)

= i + 2j

Thus,

W = F.r  

= - K - 2K

= - 3K

Answer: Thus, the work done in potential is -3K.