Question

The work-done in moving a particle in the force field f = 3 x 2 i + ( 2 x z y ) j + z k along the straight line joining the points (0, 0, 0) and (2, 1, 3) is

Answer 1

Answer:

16

Explanation:

the answer of line integral is 16

Answer 2

Disclaimer:

I think that there is a slight mistake in the question. It should be

F=3x^2 ⅈ+(2xz-y)j+zk

Concept:

Work done in moving a particle in the force field is

W= ∫F⋅ⅆr

Given:

F=3x^2 ⅈ+(2xz-y)j+zk

Straight line from (0,0,0) to (2,1,3)

Solution:

Since line is passing from (0,0,0) to (2,1,3) so

X=2t , y=t and z= 3t

Where t is number such that 0<=t<=1

Now work done (W)= ∫F⋅ⅆr

Hence the answer is 16.

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