Physics, asked by vagdevigaar, 20 days ago

The work done in pulling up a block of wood weighing 2kN for length of 10m on smooth incline plane at angle 30 degree with horizontal​

Answers

Answered by Ujjwal202
6

5.176 kN-m or Joules

Correct Question:

The work done in pulling up a block of wood weighing 2kN for length of 10m on smooth incline plane at angle 30 degree with horizontal

Step by step explanation:

Given:

Work done is equal to Force acting on a load multiplied by the displacement of the load in the direction of Force. Work is done against gravity (vertical direction)

Solution:

The component of displacement in vertical direction: h cos(90- Ф)

   = 10 meters * Cos(90- 15) deg  = 2.588 meters

Work done = Force * displacement = 2 kN * 2.588 meters = 5.176 kN-m or Joules

Hence, work done is 5.176 kN-m or Joules

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0

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