the work done in slowly pulling up a block weighing 2KN for a length of 10m on a smooth plane inclined at an angle of 15 degree with the horizontal by a force parallel to the incline is
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Option (B) 5.17 kJ...
Here friction is not considered and gravitational field is conservative field, so work done is independent of path.
Object is moved to the height (h) = s sin theta, where s is the length of the inclined plane.
W=mgh, or, W= mg(s sin theta),
or, W = 2 * 1000 * sin 15 degree * 10 = 5.17 kJ
Here friction is not considered and gravitational field is conservative field, so work done is independent of path.
Object is moved to the height (h) = s sin theta, where s is the length of the inclined plane.
W=mgh, or, W= mg(s sin theta),
or, W = 2 * 1000 * sin 15 degree * 10 = 5.17 kJ
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Explanation:
Angle is 15 degree and weight of wood is 2kN so the work done is 5.47 kilo joule
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