the work done in stretching q spring of spring constant 100N/M through a length of 10cm is
Answers
Answered by
3
Answer:
Wd = f * s
Wd = 1000 * 10
Wd = 10000J
mark as a brainlist
Answered by
1
Answer:
Given that,
Spring constant k=100
Mass m=10kg
Stretching x=2m
We know that,
The work done is
W= 1/2kx2
W= 1/2 ×100×4
W=200J
Hence, the work done is 200 J
Explanation:
please mark as brain list
Similar questions