Physics, asked by tulasitulasi3, 6 months ago

the work done in stretching q spring of spring constant 100N/M through a length of 10cm is​

Answers

Answered by shivamraj77
3

Answer:

Wd = f * s

Wd = 1000 * 10

Wd = 10000J

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Answered by tuktuki8
1

Answer:

Given that,

Spring constant k=100

Mass m=10kg

Stretching x=2m

We know that,

The work done is

W= 1/2kx2

W= 1/2 ×100×4

W=200J

Hence, the work done is 200 J

Explanation:

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