Question

The work done in taking a charge of 1 C from X to Y is​

Answer 1

Concept

• The electric field produced by a point charge will spreaded in a spherical manner surrounding itself.
• So we draw a sphere at each distance from it 'r' , we will spherical sphells.
• In each sphere, the surface of sphere of some radius(R) at each point will have same electric field.
• Those spherical shells are the equipotential surfaces where Electric lines perpendicular cut outwards.

Solution:

$\implies\rm W_{ext} = - q\Delta{V}$

$\implies\rm W_{ext} = - q\Delta{V}$

According to points we can say that potential at X and Y is same.

$\: \: \: \: \: \: \: \: \: \: \therefore V_x = V_y = V$

$\implies\rm W_{ext} = - q(V_{final}-V_{initial})$

$\implies \rm W_{ext} = -q(V_y -V_z) = -q(V-V)$

$\implies\bf WORK \: DONE = 0 \:Joule$

★ work done in taking a charge of 1 C from X to Y is Zero.

Answer 2

Explanation:

Concept

• The electric field produced by a point charge will spreaded in a spherical manner surrounding itself.
• So we draw a sphere at each distance from it 'r' , we will spherical sphells.
• In each sphere, the surface of sphere of some radius(R) at each point will have same electric field.
• Those spherical shells are the equipotential surfaces where Electric lines perpendicular cut outwards.

Solution:

$\implies\rm W_{ext} = - q\Delta{V}$

$\implies\rm W_{ext} = - q\Delta{V}$

According to points we can say that potential at X and Y is same.

$\: \: \: \: \: \: \: \: \: \: \therefore V_x = V_y = V$

$\implies\rm W_{ext} = - q(V_{final}-V_{initial})$

$\implies \rm W_{ext} = -q(V_y -V_z) = -q(V-V)$

$\implies\bf WORK \: DONE = 0 \:Joule$

★ work done in taking a charge of 1 C from X to Y is Zero.