Question

the work done in twisting is a steel of ​

Answer 1

Answer:

Length of steel wire l=0.25m

Radius of wire r=2×10

−3

m

θ=45×

180

π

Work done=

2

1

Cθ

2

C=

2l

πηr

4

C=

2×0.25m

π8×10

10

N/m

2

(2×10

−3

m)

4

C=8.0424Nm

Put the value of C in the equation for Work,

W=

2

1

(8.0424Nm)(

4

π

)

2

W=2.48Joule

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