Question

The work done in twisting steel of length 0.25 m and radius 1 mm
through an angle of 45° is in 8 x 1010 pascal)​

Answer 1

Answer:

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Explanation:

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Answer 2

Given

Length of steel wire length = 0.25m

Radius of steel 1mm

To find

The work done in twisting length of steel

Solution

We can simply solve this mathematical problem by using the following mathematical process.

We know

θ = 45 × π/180

Work done = $\frac{1}{2}$ Cθ^2

= 3.14 × 8 × $10^{10}$ × (2 × $10^{-3}$)^4 × (π/4)^2/ 4 × 25 × 10^-2

= 2.48 J

Hence, Work done is 2.48 J in twisting steel of length.

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