Physics, asked by lily9142, 2 months ago

The work done on an object is 120 J when a force of 40 N is applied on it . Fund the displacement .​

Answers

Answered by Anonymous
3

Answer:

3 m

Explanation:

As per the information provided in the question, We have:

  • Work done of an object = 120 J
  • Force = 40 N

We are asked to find displacement.

In order to find displacement, We will use the formula given below.

\qquad\:\star\;\underline{\boxed{\pmb{\sf{\bigg \lgroup W = FS \bigg\rgroup }}}}

Where,

  • W denotes work done
  • F denotes Force
  • S denotes displacement

Substituting the values.

  \begin{gathered} \implies \sf  120=40 \times  S  \\\\\\ \implies \sf   S  =  \dfrac{120}{4} \\  \\  \\ \implies {  \pmb{    \boxed{ \frak{ \red{S  =  3 \: m}} }}}\end{gathered}

Displacement is 3 m.

More to know :

  • \begin{gathered}\qquad \sf \: ( I )\: ma \bigg\lgroup \dfrac{v^2 - u^2 }{2a}\bigg \rgroup\:\\\\\end{gathered}

  • \begin{gathered}\qquad \sf \: ( II ) \: K.E = \dfrac{1}{2}mv^2\:\:\:\\\\\end{gathered}

  • \begin{gathered}\qquad \sf \: ( III ) \:\:v^2 - u^2 = 2gs\:\\\\\end{gathered}

  • \begin{gathered}\qquad \sf \: ( IV ) \:\:\:s = \dfrac{1}{2}(u + v) t \:\\\\\end{gathered}
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