Question

the work done required to stop the car of mass 1000 kg moving at a velocity 20 metre per second will be​

Answer 1

Question :

The work done required to stop the car of mass 1000 kg moving at a velocity 20 meter per second will be​  ?

Given :

• Mass of car (m) = 1000 kg
• Initial velocity of car (u) = 20 m/s

To find :

• Work done required to stop the car

Solution :

Work done required to stop the car means change in kinetic energy required to stop the car.

Here, final speed of car = 0 m/s [As it stops]

So from formula we know,

⇒ Change in Kinetic Energy, ΔK.E. = 1/2 mv² - 1/2 mu²

Putting values,

⇒ ΔK.E. = 1/2 * 1000 * (0)² - 1/2 * 1000 * (20)²

⇒ ΔK.E. = (500 * 0) - (500 * 400)

⇒ ΔK.E. = 0 - 200000 J

⇒ ΔK.E. = - 200000 J

⇒ ΔK.E. = -200000/1000 KJ

⇒ ΔK.E. = - 200 KJ

[Here negative sign shows it is working from the opposite side]

∴ Work done required = 200000 J or 200 KJ

Answer 2

Answer:

200 kj

Explanation:

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