Question

The work done to carry a charge of 0.5c from a point where the potential is-20v to another point where potential is not know is 200bj calculate the potential

Answer 1

Answer:

380 volt i think

Explanation:

w =q×[v1-v2]

Answer 2

Answer:

The point of final potential is 380V.

Explanation:

Given the work done in carrying a charge is  $q=0.5C$

Potential at a point is $V_1=-20V$

Assuming the value given for work done is $W=200J$

Electric potential or potential difference is defined as the work done to bring a test charge from one point to another point.

Mathematically written as, $V_2-V_1=\frac{W}{q}$

Substituting the values,

$\implies V_2-(-20)=\frac{200}{0.5}$

$\implies V_2+20=400$

$\implies V_2=400-20=380V$

Therefore, the final potential is 380V.