Question

the work done to take an electon from rest where potential is -60 volt to another point where potential is -20 volt is given​

Answer 1

Answer: 64×10^(-19) Joule

Explanation:We know ∆V= W/Q

So W=∆VQ

=(-20-(-60)) ×1.6×10^(-19)

=40×1.6×10^(-19)

=64×10^(-19) Joule

Answer 2

ANSWER:

GIVEN : V1= -60V

V2= -20V

WORK DONE = (DELTA V)e

                       =(V1 - V2)e

                       =[(-60)-(-20)]e

                       = -40eV