Question

The work done when 6.5 g of zinc reacts with dil HCL in an open beaker at 298 K is?

Answer 1

Answer: The work done when 6.5 g of zinc reacts with dil HCL in an open beaker at 298 K is -249.27 joules.

Explanation:

According to the ideal gas equation P V = n R T.

As the beaker is open, therefore the pressure inside the beaker equals the atmospheric pressure which is 1 atm.

Calculate the volume as follows.

        $1 atm \times V = 0.1 \times (0.0821 L atm /mol K) \times 298 K$

                            V = 2.56 litre

The equation for work done = $P_{ext}V$

                                               = $-1 atm \times 2.46 litre$

                                              = -2.46 litre atm                               

It is known that 1 litre atmosphere equals 101.33 joules. Therefore, converting  -2.46 litre atm into joules as follows.

               $-2.46 litre atm \times 101.33 joules$

               = -249.27 joules

Thus, the work done when 6.5 g of zinc reacts with dil HCL in an open beaker at 298 K is -249.27 joules.

Answer 2

Answer:

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