Question

The work done when 6.5 grams of zinc reacts with dilute HCl in an open the core 298 Kelvin is

Answer 1

Explanation:

Solution:-

No. of moles = 6.5/65 = 0.1 mol

W = -P×V = -1 × V = -V

Implies that:-

-nRT /9 = (-0.1× 0.0821× 298)/1

= -2.44658 joules

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