Question

the work done when 6.5g of zinc reacts with dilHcl is an open beaker at 298K

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Answer 1

The work done when 6.5 g of zinc reacts with dil. HCl is an open beaker at 298 K is:

$\mathtt{number \: of \: moles = \frac{6.5}{65} = 0.1 \: moles} \\ \\ \mathtt{w = - p \times v = - 1 \times v = - v} \\ \\ \implies\mathtt{ \frac{ - nrt}{9} } \\ \\ \mathtt{ = \frac{ - 0.1 \times 0.0821 \times 298}{9} } \\ \\ \mathtt{ = - 2.44658 \: j \: \: ans}$