Question

The work done when 6.5g of zinc reacts with dilute hcl in an open beaker at 298k is?

Answer 1

The work done when 6.5g of zinc reacts with dilute HCl in an open beaker at 298k is -2.44658 Joules.

First, the number of moles of zinc needs to be determined.

Moles of zinc = 6.5/65 = 0.1mol

After that = – P*V = -1*V = -V

= -nRT/P

= -0.1*0.0821*298/1

= -2.44658 Joules