The work done when a force of [F=(2i + 3j – 5k)] unit acting on a body produces a displacement [S=(2i + 4j + 3k)] unit is
30 unit
2 unit
1 unit
Zero
Answers
Explanation:
Wrok done = force . displacement.
so,
force = (2i + 3j – 5k)
Displacement = (2i + 4j + 3k)
work done = (2i + 3j – 5k).(2i + 4j + 3k)
so, work done = 4+12-15
work done = 1 joule
Answer:
The work done is 1 Joule.
The work done on a system by a constant force is the component of force in the motion times the displacement through which the force acts.
Work done is said to be 1 J when a force of 1 N is moved through a displacement 1 m along the direction of force.
The formula for work done is given as W = F × s
where, F is the force
s is the displacement
F = (2i + 3j – 5k)
S = (2i + 4j + 3k)
Work done = Force . displacement
Work = (2i + 3j – 5k).(2i + 4j + 3k)
Work = 4 + 12 - 15
Work = 16 - 15
Work = 1 Joule
The work done will be 1 Joule.
To know more about work, refer: https://brainly.in/question/1917775
To know further about force, refer: https://brainly.in/question/47738337
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