Question

The work done when three moles of an ideal gas are expanded isothermally from 15 dm3 to 20 dm3 at constant external pressure of 1.2 bar is …..

Answer 1

at constant external pressure of 1.2 bar. Estimate the

W = - Pext ∆V = - Pext (V2 - V1)

Pext = 1.2 bar, V1= 15 dm3, V2 = 20 dm3

Substitution of these quantities into the

equation gives

W = -1.2 bar (20 dm3 - 15 dm3)

= -1.2 bar × 5dm3

= -6 dm3bar1 dm3

bar = 100 J

Hence, W = -6 dm3

bar × 100 J/dm3

bar = -600 J

Answer 2

Answer:

see the attachment

Explanation:

hope it will help uh