The work function for a metal is 4 eV. To
eject a photoelectron of zero velocity
from the surface of the metal, the
wavelength of incident light should be
above
describe in chemistry method
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2
Answer:
hv=hv0+KE for zero velocity KE=0
hv=hv0
hv=4eV
λhc=4eV
λ=4eVh×c
=4×1.6×10−196.626×10−34×3×108=3100Ao
Hence, the correct option is D
Answered by
2
Answer:
Did you mean: The work function for a metal is 4eV. To eject a photoelectron of zero velocity from the surface of the metal, the wavelength of incident light should be above describe in chemistry method
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