Question

The work function of a metal is 2.8ev. Whati is its threshold wavelength

Answer 1

Answer:

Hey... here is your answer

Explanation:

Answer 2

Threshold wavelength is approximately 442 nm

Explanation:

• In radioactive material photons or sunlight incident on a given photosensitive material if the work function overcome  by the energy of incident wave then we get photoelectric current due to the emission of photo electrons from the given surface otherwise electrons will not get ejected from the metal surface
• Energy of given function is given as E = hν

Given, work function = 2.8 e V

work function = 2.8 * 1.6 ×10⁻¹⁹ J

h = 6.6 × 10⁻³⁴ J s

=> E = hν

=> also c= νλ

=> ν = c/λ

where c = speed of light in vacuum

c = 3 ×10⁸ m/s

λ = wavelength

ν = frequency

=> E = h c/λ

=> 2.8 * 1.6 ×10⁻¹⁹ = 6.6 × 10⁻³⁴ ×3 ×10⁸ / λ

=> λ = $\frac{6.6*10^{-34}*3*10^{8} }{2.8 *1.6 * 10^{-19}}$

=> λ = $\frac{19.8 *10^{-7} }{4.48}$

=> λ = 4.42 *10⁻⁷ m

or λ = 442 n m

To know more about threshold wavelength, visit:

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