Physics, asked by itachiuchihaxx, 7 months ago

The Work function of a metal is 3.3eV then the threshold frequency is
(A) 8 × 10^14 Hz

(C) 5 × l0^10 Hz

(B) 8 × 10^20 Hz

(D) 4 × 10^14 Hz​

Answers

Answered by WhoEver
1

Work function of the metal = 3.3 eV

We know that ,

Work Function = Threshold Frequency × Plank's constant

W = hV

V =  \frac{W}{h}  \\  V =  \frac{3.3 \times  {10}^{ - 19} }{6.6 × {10}^{ - 34} } (We put the value of e = 1.6 ×  {10}^{ - 19})  \\  → 8 ×  {10}^{14}

Required answer = Option A

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