Question

The work function of a metal is 4.2 ev .if the radiation of 2000°A falls on a metal find the June if energy

Answer 1

Answer:

Explanation:

Pls refer the below attachment for your answer...

Hope it helps you

Please make it as the brainliest ☺️

Answer 2

The energy is $3.22\times 10^{-19}\ J$.

Explanation:

The Einstein's photoelectric equation is given by :

$\dfrac{hc}{\lambda}=E+W_o$........(1)

Here,

h is Planck's constant

c is speed of light

$\lambda$ is wavelength

E is energy

$W_o$ is work function of metal

We have, the work function of a metal is 4.2 eV.

The wavelength of radiation is 2000 A

It is required to find the energy of radiation. So, using equation (1) we get :

$E=\dfrac{hc}{\lambda}-W_o\\\\E=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{2000\times 10^{-10}}-4.2\times 1.6\times 10^{-19}\\\\E=3.22\times 10^{-19}\ J$

So, the energy is $3.22\times 10^{-19}\ J$.

Learn more,

Einstein's equation

https://brainly.in/question/2348207